NEET 2026 Chemistry Question 56
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Question
The strandard electrode potential (E° for the half- cell reaction Fe* + ¢” — Fe** at 298 K is (Given : E(Fe*/Fe) = -0.04 V and E%Fe’/Fe) = -0.44 V at 298 K)
Options
- 1+0.40V
- 2+0.76 V
- 3-0.48V
- 4+0.92V
Supplied answer marker
Option 2 - +0.76 V
Explanation
Explanation will be updated after review.

